How do you find force per unit length?

The force per unit length can then be calculated using the known currents in the wires: Fl=(4π×10−7T⋅m/A)(5×10−3A)2(2π)(5×10−2m)=1×10−10N/m.

How do you find the unit length of a magnetic force?

If we divide both sides of this expression by l, we find that the magnetic force per unit length of wire in a uniform field is Fl=IBsinθ F l = I B sin ⁡ . The direction of this force is given by RHR-1, with the thumb in the direction of the current I.

What does force per unit length mean?

The ratio F/l is the force per unit length between two parallel currents I1 and I2 separated by a distance r. The force is attractive if the currents are in the same direction and repulsive if they are in opposite directions. This force is responsible for the pinch effect in electric arcs and other plasmas.

What is the force acting per unit current length?

F/l is the force per unit length between two parallel currents I1 and I2 separated by a distance r. The force is attractive if the currents are in the same direction and repulsive if they are in opposite directions. This force is responsible for the pinch effect in electric arcs and plasmas.

What is the force per unit area called?

This quantity is known as pressure. Pressure is the ratio of the normal force or thrust on a surface acting per unit area of the surface.

What is the volume of solenoid?

Cylindrical Solenoid L=μ0(Nl)2Al=μ0n2Al=μ0n2(V), where V=Al is the volume of the solenoid. Notice that the self-inductance of a long solenoid depends only on its physical properties (such as the number of turns of wire per unit length and the volume), and not on the magnetic field or the current.

What is the force per unit length between the wires?

This force between two current carrying wires gives rise to the fundamental definition of the Ampère: If two long parallel wires 1 m apart each carry a current of 1 A, then the force per unit length on each wire is 2 x 10- 7 N/m.

How many turns does a solenoid have in it?

A solenoid has 300 turns wound around a cylinder of diameter 1.20 cm and length 14.0 cm. If the current through the coils is 0.410 A, what is the magnitude of the magnetic field inside and near the middle of the solenoid?

How to calculate the magnetic field of a solenoid?

We first calculate the magnetic field at the point P of Figure 12.19. This point is on the central axis of the solenoid. We are basically cutting the solenoid into thin slices that are dy thick and treating each as a current loop. Thus, dI is the current through each slice.

Is the net current inside a solenoid zero?

Outside the solenoid, one can draw an Ampère’s law loop around the entire solenoid. This would enclose current flowing in both directions. Therefore, the net current inside the loop is zero. According to Ampère’s law, if the net current is zero, the magnetic field must be zero.

How is the solenoid field related to ampere’s law?

Solenoid Field from Ampere’s Law Taking a rectangular path about which to evaluate Ampere’s Lawsuch that the length of the side parallel to the solenoid field is L gives a contribution BL inside the coil. The field is essentially perpendicular to the sides of the path, giving negligible contribution.